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Compare a string with the string.
template< [role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type]> constexpr int compare( const T& t) const;
            Let s be string_view_type(t)
            and comp be traits_type::compare(data(),
            s.data(), std::min(size(),
            s.size()) . If comp != 0, then
            the result is comp. Otherwise,
            the result is 0 if size()
            == s.size() , -1
            if size()
            < s.size() , and 1 otherwise.
          
Linear.
Strong guarantee.
| Type | Description | 
|---|---|
| 
                       | The type of the object to convert. | 
std::is_convertible<const T&, string_view>::value && !std::is_convertible<const T&, const_pointer>::value.
            The result of lexicographically comparing s
            and the string.
          
| Name | Description | 
|---|---|
| 
                       | The string to compare. |