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Return a pointer to the value if the key is found, or null.
value const* if_contains( string_view key) const;
This function searches for a value with the given key, and returns a pointer to it if found. Otherwise it returns null.
if( auto p = obj.if_contains( "key" ) ) std::cout << *p;
            Constant on average, worst case linear in size().
          
No-throw guarantee.
| Name | Description | 
|---|---|
| 
                       | The key of the element to find. |