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Compare a string with the string.
template< [role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type][role red error.param neither has a declname nor a 'class ' prefix in the type]> constexpr int compare( size_type pos1, size_type count1, const T& t, size_type pos2, size_type count2 = npos) const;
            Let sub1 be substr(pos1, count1),
            sub2 be string_view_type(t).substr(pos2, count2),
            and comp be traits_type::compare(sub1.data(), sub2.data(), std::min(sub1.size(), sub2.size()).
            If comp !=
            0, then the result is comp. Otherwise, the result is 0 if sub1.size() == sub2.size(),
            -1
            if sub1.size() < sub2.size(), and 1
            otherwise.
          
Linear.
Strong guarantee.
| Type | Description | 
|---|---|
| 
                       | The type of the object to convert. | 
std::is_convertible<const T&, string_view>::value && !std::is_convertible<const T&, const_pointer>::value.
            The result of lexicographically comparing sub1
            and sub2.
          
| Name | Description | 
|---|---|
| 
                       | The index at which to begin the substring in the string. | 
| 
                       | The length of the substring in the string. | 
| 
                       | The string to compare. | 
| 
                       | The index at which to begin the substring in the string view. | 
| 
                       | The length of the substring in the string view. |